Assume you have a sealed jug that only contains air. if you heat the air in the jug it will have a higher temperature. what are other properties of air will change?
a: air volume
b: air density
c: air composition
d: air pressure

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.

                             

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters

A- electron repulsion favors a tetrahedral shape, so the orbitals are 109.5° apart from each other. of a hydrogen atom on methane. they may also contain lone pairs—this explains the geometry of water, which is sp3 hybridized due to the lone pair, which occupies one of the four hybrid orbitals.