Amixture of 2 moles of ne gas and 3 moles of ar gas are kept in a cylinder at 25.0 degress celcious. what is the indivual pressure of each and the total pressure?

Hey there!

Assuming the volume of the cylinder is 1 L.  

Given, T=25 = 298K  

As per the Dalton's law, total P = PNe + PAr  ...where PNe = partial pressure of Ne and PAr = partial pressure of Ar.  

PV = nRT  

total P = (total moles)* (0.082057 L atm mol-1K-1 * 298)/1 = 5*0.082057*298 = 122.27 atm.  

PNe = mole fraction of Ne * total P = (2/5)*122.27 = 48.908 atm  

PAr = mole fraction of Ar * total P = (3/5)*122.27 = 73.362 atm  

Total pressure is 122.27 atm  

Ne pratial pressure = 48.908 atm

Ar prtial pressure = 73.362 atm

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante

the right answer is c i just did the question.