Which of the following orbitals is possible in an electron configuration? 4p 1p 3f o 2d

4p

Explanation:

The possible orbitals in an electronic configuration must include:

A principle quantum number (n) , azimuthal quantum number (l) which is (0-n-1) , magnetic quantum number (m) which is (-l to +l) and spin quantum number.

Taking about 1p

n = 1

Possible value of l = 0 which is s orbital. Hence, it is not possible.

Taking about 3f

n = 3

Possible value of l = 0 , 1 and 2 which is s , p and d orbitals. Hence, it is not possible.

Taking about 2d

n = 2

Possible value of l = 0 and 1 which is s and p orbitals. Hence, it is not possible.

The only possible is 4 p in which all quantum numbers are justified.

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )