3. calculate the potentiai of the cell indicated using the line notation below. pt(s) 12(s)|1 (aq, 1.0 m) || cr2o,2-(aq, 2.0 m), cr (aq, 1.0x10 m), h'(aq, 1.0 m)| pt(s) cr2o72 (aq)+14h*(aq) + 6e + 2cr (aq)+7h20() e+1.33 v eo +0.54 v 2(s)2e 21(aq) +

c, liquids evaporate, creating a gas

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally