Determine the empirical formulas for compounds with the following percent compositions:
(a)15.8% carbon and 84.2 percent sulfur
(b)40.0 percent carbon, 6.7% hydrogen, and 53.3% oxygen

a)  

b)

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C =

Moles of S=

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For S =

The ratio of C  : S = 1:2

Hence the empirical formula is

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For O =

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is

to make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 ml of water at 80 degrees celsius. when the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.