Determine the molarity for each of the following solution solutions:
(a)1.457 mol of kcl in 1.500 l of solution
(b) 0.515 gram ofh2so4, in 1.00 l of solution
(c) 20.54 g of al(no3)3 in 1575 ml of solution
(d)2.76 kg ofcuso4.5h2o in 1.45 l of solution
(e)0.005653 mol ofbr2 in 10.00 ml of solution
(f) 0.000889 g of glycine, c2h5no2, in 1.05 ml of solution

Answer :

(a)The molarity of KCl solution is, 0.9713 mole/L

(b)The molarity of solution is, 0.00525 mole/L

(c)The molarity of solution is, 0.0612 mole/L

(d)The molarity of solution is, 7.61 mole/L

(e)The molarity of solution is, 0.0565 mole/L

(f)The molarity of solution is, 0.0113 mole/L

Explanation :

(a) 1.457 mol of KCl in 1.500 L of solution

Formula used :

Solute is KCl.

The molarity of KCl solution is, 0.9713 mole/L

(b) 0.515 gram of , in 1.00 L of solution

Formula used :

Solute is

Molar mass of = 98 g/mole

The molarity of solution is, 0.00525 mole/L

(c) 20.54 g of in 1575 mL of solution

Formula used :

Solute is

Molar mass of = 213 g/mole

The molarity of solution is, 0.0612 mole/L

(d) 2.76 kg of in 1.45 L of solution

Formula used :

Solute is

Molar mass of = 250 g/mole

The molarity of solution is, 7.61 mole/L

(e) 0.005653 mol of in 10.00 ml of solution

Formula used :

Solute is .

The molarity of solution is, 0.0565 mole/L

(f) 0.000889 g of glycine, , in 1.05 mL of solution

Formula used :

Solute is

Molar mass of = 75 g/mole

The molarity of solution is, 0.0113 mole/L

petroleum? coal maybe?