Considered this question: what is the mass of solute in 200.0 l of a 1.556-m solution of kbr?
(a) outline the steps necessary to answer the question
(b) answer the question

Hey there!:

a )

number of moles of solute :

moles of solute = molarity  x volume ( L )

moles of solute = 1.556 x 200.0

moles of solute = 311.2 moles of  KBr

b) Molar mass of KBr : 119.002 g/mol

1 mole KBr 119.002 g

311.2 moles ( mass KBr ) ?

mass glucose = 311.2 x 119.002 / 1

mass glucose => 37033.4224 g

po-215 i got it right on the quiz