What is the ph of a 0.0288 m solution of ammonia (kb 1.8 x 10-5)?

10.86

Explanation:

Given that:

Concentration = 0.0288 M

Consider the ICE take for the dissociation of ammonia as:

                                      NH₃    +   H₂O    ⇄     NH₄⁺ +    OH⁻

At t=0                          0.0288                             -              -

At t =equilibrium        (0.0288-x)                         x           x            

The expression for dissociation constant of ammonia is:

x is very small, so (0.0288 - x) ≅ 0.0288

Solving for x, we get:

x = 7.2×10⁻⁴  M

pOH = -log[OH⁻] = -log(7.2×10⁻⁴) = 3.14

Also,

pH + pOH = 14

So, pH = 10.86

people flirt to show their affection towards someone in a less forward way then telling. they want the other person to guess what they’re feeling to have the other person also start to like them

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.