What is the molarity of the dilute solution when each of the following solution related to the given final volume?
(a) 1.00 l of a 0.250-m solution of fe(no3)3 is diluted to a final volume of 2.00l
(b)0.5000 l of a 0.1222-m solution of c3h7oh isdiluted to a final volume of 1.250 l
(c)2.3 5 l of a 0.350-m solution of h3po4 diluted to a final volume of 4.00 l
(d)22. 50 ml of 0.025-m solution of c12h22o11 is diluted to 100.0 ml

a) 0.125 M

b) 0.04888 M

c) 0.2056 M

d)  0.005625 M

Explanation:

(a) Given:

V₁ = 1.00 L

M₁ = 0.250-M

V₂ = 2.00 L

Now,

We know,

M₁V₁ = M₂V₂

where, M₂ is the molarity of the final solution

Thus,

0.250 × 1.00 = M₂ × 2.00

or

M₂ = 0.125 M

b) Given:

V₁ = 0.5000 L

M₁ = 0.1222-M

V₂ = 1.250 L

Now,

We know,

M₁V₁ = M₂V₂

Thus,

0.1222 × 0.5000 = M₂ × 1.250

or

M₂ = 0.04888 M

c) Given:

V₁ = 2.35 L

M₁ = 0.350 M

V₂ = 4.00 L

Now,

We know,

M₁V₁ = M₂V₂

Thus,

0.350 × 2.35 = M₂ × 4.00

or

M₂ = 0.2056 M

d) Given:

V₁ = 22.50 L

M₁ = 0.025 M

V₂ = 100.0 L

Now,

We know,

M₁V₁ = M₂V₂

Thus,

0.025 × 22.50 = M₂ × 100.0

or

M₂ = 0.005625 M

your answers are a,b,,e and f

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for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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