Magnesium will burn in air to form both mg3n2 and mgo. what mass of each product would be found if burning a 3.26 g sample of magnesium to completion produces a combined total of 5.09 g of the two products

The mass of MgO formed is 3.502 grams and mass of formed is 1.587 grams.

Explanation:

We are given:

Total mass of magnesium reacted = 3.26 g

Total mass of products formed = 5.09 g

To calculate number of moles of a substance, we use the equation:

     .....(1)

For calculating mass of MgO:

The chemical equation for the formation of magnesium oxide follows:

Let 'x' grams of magnesium is reacting to form magnesium oxide.

Molar mass of Magnesium = 24.3 g/mol

Putting values in equation 1, we get:

Number of moles of magnesium =

By Stoichiometry of the reaction:

2 moles of magnesium produces 2 moles of MgO

So, moles of magnesium will produce moles of MgO

Molar mass of MgO = 40.3 g/mol

Putting values in equation 1, we get:

Mass of MgO =

Mass of magnesium oxide = = X grams

For calculating mass of :

The chemical equation for the formation of magnesium nitride follows:

Mass of magnesium reacting = (3.26 - x)

Molar mass of Magnesium = 24.3 g/mol

Putting values in equation 1, we get:

Number of moles of magnesium =

By Stoichiometry of the reaction:

3 moles of magnesium produces 1 moles of

So, moles of magnesium will produce moles of

Molar mass of = 101 g/mol

Putting values in equation 1, we get:

Mass of

Mass of magnesium nitride = = Y grams

Calculating the mass of products:

Total mass of the products = 5.09 grams

Putting values of 'X' and 'Y' in above equation, we get:

Mass of MgO =

Mass of

Hence, the mass of MgO formed is 3.502 grams and mass of formed is 1.587 grams.

Abbreviated as mg-25.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !