Online steps needed to determine the limiting reactant when 0.50g of cr and 0.75 g h3po4 react according to the following chemical equation?
2cr + 2h3po4 ? 2crpo4 + 3h2
determine the limiting reactant.

Answer : The limiting reactant is .

Explanation : Given,

Mass of = 0.50 g

Mass of = 0.75 g

Molar mass of = 52 g/mole

Molar mass of = 98 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 2 mole of

So, 0.00765 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Hence, the limiting reactant is .

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

your answer is c) plasma

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