What volume of 0.08892 m hno3 is required to react completetly with 0.2352 g of potassium hydrogen phosphate?
2hno3 + k2hpo4 ? h2po4 + kno3

The volume of nitric acid is 0.025 L.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of KHP = 0.2352 g

Molar mass of KHP = 204.22 g/mol

Putting values in above equation, we get:

The chemical reaction for the formation of chromium oxide follows the equation:

By Stoichiometry of the reaction:

1 mole of potassium hydrogen phosphate reacts with 2 mole of nitric acid

So, 0.0011 moles of potassium hydrogen phosphate will react with = of nitric acid

To calculate the volume of nitric acid, we use the equation:

We are given:

Moles of Nitric acid = 0.0022 moles

Molarity of solution = 0.08892 M

Putting values in above equation, we get:

Hence, the volume of nitric acid is 0.025 L.

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