How many grams of koh are there in 250 milliliters of 0.05m aqueous solution of this substance

Explanation:

Also, we know that molarity is the number of moles present in a liter of solution.

           Molarity =

                   0.05 m =    (as 1 ml = 0.001 L)

                   no. of moles = 0.0125 mol      

It is known that number of moles equal mass divided by molar mass. And, molar mass of KOH is 56.10 g/mol.

Hence,  No. of moles =

                0.0125 mol =

                   mass = 0.701 g

Thus, we can conclude that there are 0.701 g of KOH are there in 250 milliliters of 0.05m aqueous solution of this substance.

it's filtration, but this is an assumption so my apologies if i got this