11. silver metal may be precipitated from a solution of silver nitrate by placing a copper strip into the solution. what mass of nano3 would you dissolve in water in order to get 1.00 g of silver?

The mass of silver nitrate that must be dissolved is 1.58 grams.

Explanation:

To calculate the number of moles, we use the equation:

  ......(1)

Given mass of silver = 1 g

Molar mass of silver = 107.86 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of silver nitrate and copper follows:

By Stoichiometry of the reaction:

2 moles of silver is produced from 2 moles of silver nitrate

So, 0.0093 moles of silver will be produced from = of silver nitrate

Now, calculating the mass of silver nitrate from equation 1, we get:

Molar mass of silver nitrate = 169.87 g/mol

Moles of silver nitrate = 0.0093 moles

Putting values in equation 1, we get:

Hence, the mass of silver nitrate that must be dissolved is 1.58 grams.

particle   p is an electron and particle q is a neutron

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b