Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2al(s)+3cl2(g)→2alcl3(s) what is the maximum mass of aluminum chloride that can be formed when reacting 21.0 g of aluminum with 26.0 g of chlorine?

32.6 g AlCl₃

Explanation:

First, the limiting reagent must be found by determining the moles of aluminum and the moles of chlorine. The atomic/molecular weights of Al and Cl₂ are 26.9815 g/mol and 70.9060 g/mol, respectively.

Al: (21.0 g) / (26.9815 g/mol) = 0.778 mol Al

Cl₂: (26.0g) (70.9060 g/mol) = 0.367 mol Cl₂

The amount of Cl₂ required to react with 0.778 mol Al is 1.167 mol, based on the molar ratio (see below). Therefore, Cl₂ is the limiting reagent.

(0.778 mol Al) x (3Cl₂/2Al) = 1.167 mol Cl₂

The amount of aluminum chloride formed is based on the amount of limiting reagent available:

(0.367 mol Cl₂)(2AlCl₃/3Cl₂) = 0.2446 mol AlCl₃

Finally, the mass of AlCl₃ can be calculated using the molecular weight (133.34 g/mol):

(0.2446 mol)(133.34 g/mol) = 32.6 g AlCl₃

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

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