Achemist measures the amount of bromine liquid produced during an experiment. she finds that 14.4 g of bromine liquid is produced. calculate the number of moles of bromine liquid produced.
round your answer to 3 significant digit

The number of mole of bromine liquid produced is 0.09 mole  

The mole of an element as it relates to its mass and molar mass, can be obtained by using the following equation:

With the above formula, we can obtain the number of mole bromine liquid produced. This can be obtained as follow:

Mass of bromine liquid (Br₂) = 14.4 g

Molar mass of bromine liquid (Br₂) = 2 × 80 = 160 g/mol

Mole = mass / molar mass

Mole of bromine liquid = 14.4 / 160

Therefore, the number of mole of bromine liquid produced is 0.09 mole

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Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied