One side of a cube of an unknown metal measures 0.53cm. if the mass of the cube is 0.92g, what is the density of the cube?

6.174 g/cm³

Explanation:

First we calculate the volume of the cube:

volume = edge × edge × edge

volume = 0.53 × 0.53 × 0.53 = 0.149 cm³

Now we may proceed to calculate the density:

density = mass / volume

density = 0.92 / 0.149 = 6.174 g/cm³

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2