Iam using all my points to ask this.
a compound containing 74.0% carbon, 8.7% hydrogen and 17.3% nitrogen. determine the
empirical formula.
if the compound above has a molar mass of 162.1g/mol. determine the molecular formula of the compound

C5H7N

C10H14N2

Explanation:

ok so lets lay out this nicely

elements                                                         C              H         N                    

percentage                                                    74             8.7       17.3

mass number                                                 12              1          14

divided percentage by mass                        6.167          8.7      1.2357

now divide the smallest number with the 4.99            7.04    1

rest for instance 1,237 is the smallest.    

so 6.167÷1,237

and 8.7 ÷1.237

and 1,237 divide 1.237    

now the ratio is                              C5H7N

now for molecular formula find Mr of C5H7N which is (12×5)+7+14=81

next divide 162.1÷81=2

so now for molecular formula just multipily everythng by 2

C10H14N2

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