(you and explain! ) here are two questions:
"the most common form of nylon (nylon-6) is 63.68% carbon, 12.38% nitrogen, 9.8% hydrogen, and 14.14% oxygen. calculate the empirical formula for nylon-6."
"there are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with oxygen gas escaping into the atmosphere while leaving a residue of pure mercury. heating 0.6498 g of one of the compounds leaves a residue of 0.6018 g. heating 4.172 g of the other compound results in a mass loss of 0.016 g. determine the empirical formula of each compound."
you for your !

The answer for the first problem is:  C₆N₁H₁₁O₁ or C₆NH₁₁O

Explanation:

Nylon composition:                     Mass        Divide by the atomic mass

Carbon                   63.68 %      63.68 g         63.68/ 12    = 5.3

Nitrogen                 12.38 %       12.38 g          12.38/14     = 0.88

Hydrogen                  9.8%           9.8 g           9.8/1           = 9.8

Oxygen                    14.14%         14.14 g          14.14/16      = 0.88

We choose the lowest number that is 0.88 for nitrogen and oxygen and divide the four results by this number

Carbon     5.3/0.88 = 6

Nitrogen    0.88/0.88 = 1

Hydrogen   9.8/0.88 = 11.1  = 11

Oxygen     0.88/ 0.88 = 1  

Then the empirical formula has this coefficients

        C₆N₁H₁₁O₁ or C₆NH₁₁O

your answer would be “dry”