The reaction: (ch3)3cbr + oh− → (ch3)3coh + br− in a certain solvent is first order with respect to oh−. in several experiments, the rate constant k was determined at different temperatures. a plot of ln(k) vs 1/t was constructed and the slope of the line was -1.10 x 104 k with a y-intercept of 33.5. what is the value for k at a temperature of 25°c? a. 3.69 × 10-7 s-1 b. 3.51 s-1 c. 3.23 × 10-2 s-1 d. 1.10 × 104 s-1

C

Explanation:

This is the Arrehnius equation in lineal form, lnK = -Ea/RT + lnA.

so the slope corresponds to -Ea/R and the intercept is lnA. So from the slope we can calculate the Ea Ea=-(-1.10*10^4)*8.314=9.1*10^4 J/lol

A=e^(33.5)=3.53*10^14

Finally with these values and using the Arrehnius equation we can calculate K at 25°C.

k=Ae^-(Ea/RT)

k=(91.06)e^-(9.1*10^4/(8.314*298))

k=3.23*10^-2

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