The following substances dissolve when added to water. classify the substances according to the strongest solute-solvent interaction that will occur between the given substances and water during dissolution.
(1) ion-ion forces
(2) dipole dipole forces
(3) ion dipole forces
(4) london dispersion forces
(a) hf
(b) ch3oh
(c) cacl2
(d) febr3

Explanation:

Ion-ion forces are defined as the forces that exist between oppositely charged ions.

Dipole-dipole interactions are defined as the forces which exist between positive end of polar molecule and negative end of another polar molecule.

Ion-dipole forces are defined as the forces that exist between a charged ion and a polar molecule.

London dispersion forces are defined as the forces that arise due to the development of temporary charges on the combining atoms of a molecule.

Hence, the given substances are classified as follows.

(a) HF - It is a covalent compound but due to the difference in electronegativity of hydrogen and fluorine there will be development of partial charges on both of them.

Hence, in a HF molecule there will be dipole-dipole forces.

(b) - There will also be development of partial charges due to the difference in electronegativity of oxygen and hydrogen atoms.

Hence, in a there will be dipole-dipole forces.

(c) - It is an ionic compound. Hence, there will be partial positive charge on calcium and partial negative charge on chlorine atom.

Hence, in a molecule there will exist ion-ion forces.

(d) - It is an ionic compound. Hence, there will also exist ion-ion forces.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml