Asolution is saturated when 25.0 grams of the solute is dissolved in 100.0 grams of solvent. when a new solution is made that has 40.0 grams of solute dissolved in 160 grams of solvent, assuming a constant temperature, classify the new solution as:

Satured

Explanation:

A solution can be classified as unsaturated, saturated or supersaturated. The solvent has a maximum capacity of dissolution, so when it hasn't reached this capacity, the solution is unsaturated, when it reaches it, the solution is saturated, and when it surpasses this capacity, the solution is supersaturated.

To know the classification of a solution, we must know it's solubility coefficient, which can be calculated by dividing the amount of solute by the amount of solvent. Usually it is given by the mass of solute/100 mL of solvent, but in this case, let's calculate it in the mass of solute/mass of solvent.

When 25.0 g of solute is dissolved in 100.0 g of the solvent the solution is saturated, so the solubility coefficient will be:

25/100 = 0.25 g/g

It means that, if the mass of solute/ mass of solvent is lower than 0.25, the solution is unsaturated, if it's higher, supersaturated, and if it's equal to 0.25, saturated.

So, for 40.0 g of solute and 160.0 g of solvent:

40/160 = 0.25 g/g

And the solution is saturated.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

b. examine and describe cells