Consider the following metabolic reaction:
3-phosphoglycerate → 2-phosphoglycerate δg°’ = +4.40 kj/mol
what is the δg for this reaction when the concentration of 2-phosphoglycerate is 0.290 mm and the concentration of 3-phosphoglycerate is 2.90 mm at 37°c?

ΔG = -1.53 kJ/mol

Explanation:

The given reaction is:

3-Phosphoglycerate → 2-Phosphoglycerate

The standard Gibbs free energy, ΔG°=+4.40 kJ

[2-Phosphoglycerate] = 0.290 mM

[3-Phosphoglycerate] = 2.90 mM

Temperature T = 37 C = 310 K

The standard Gibbs free energy, ΔG° is related to the free energy change ΔG at a given temperature by the following equation:

In this reaction:

m=9

step-by-step explanation:

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