Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble to most soluble) lif < nano3 < chcl3 ch3oh < ch4 < lif ch4 < nano3 < chcl3 ccl4 < chcl3 < nano3 ch3oh < cl4 < chcl3

Option (d) is the correct answer.

Explanation:

As it is known that like dissolves like. So, water being a polar compound is able to dissolve only polar compounds.

Hence, a compound that is ionic or polar in nature will readily dissolve in water. Whereas non-polar compounds will be insoluble in water.

As is a non-polar compound. Hence, it is insoluble in water.

On the other hand, is a polar compound due to difference in electronegativity of chlorine and carbon atom there will be development of partial charges. Hence, there will be dipole-dipole forces existing between them.

Whereas is an ionic compound and it will readily dissociate into ions when dissolved in water. Also, there will be ion-dipole interactions between sodium and nitrate ions.

Hence, will readily dissolve in water.

Thus, we can conclude that the compounds correctly arranged in order of increasing solubility in water are < < .

i think   the answer is c hope i'm right