An adult eats food whose nutritional energy totals
approximately2.2*103 cal per day. the adult
burns2.0*103 cal per day. how much excess
nutritionalenergy, in kilojoules, does the adult consume per day?
if 1lb of fat is stored by the body for each
14.6*103kilojoules of excess nutritional energy
consumed, how long will ittake this person to gain 1 lb.

0.8368 kiloJoules of an excess nutritional energy is consumed by an adult in a day.

It will take 17,447.41 days long to gain 1 lb of fat by this person.

Explanation:

Calorie intake of an adult in a day =

Calorie burnt by an adult in a day =

Excess  nutritional energy in day=

1 kcal = 4.184 kJ

So , 1000 cal = 4.184 kJ

0.8368 kiloJoules of an excess nutritional energy is consumed by an adult in a day.

kilo joules of excess nutritional energy = 1 lb fat

The 1 kilo joule of excess nutritional energy  = lb fat

Excessive nutritional energy of an adult per day = 0.8368 kiloJoules

Amount of fat gained by an adult per day =

= of fat

In 1 day an adult gains = of fat

Time taken to gain 1 lb fat:

It will take 17,447.41 days long to gain 1 lb of fat by this person.

a graduated cylinder.

explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g