Asolution is to be prepared with a sodium ion concentrationof
0.148 mol/l. what mass of sodium sulfate (g) is needed toprepare
2.29 liters of such a solution?

Answer : The mass of sodium sulfate needed is 5.7085 grams.

Explanation : Given,

Concentration of sodium ion = 0.148 mol/L

Volume of solution = 2.29 L

Molar mass of sodium sulfate = 142 g/mole

First we have to determine the moles of sodium ion.

Now we have to calculate the moles of sodium sulfate.

The balanced chemical reaction will be,

As, 2 moles of sodium ion produced from 1 moles of

So, 0.08035 moles of sodium ion produced from moles of

Now we have to calculate the mass of sodium sulfate.

Therefore, the mass of sodium sulfate needed is 5.7085 grams.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

it takes on an electronical energy