Air at 320 k saturated with water vapor is dehumidified by cooling to 285 k and by 2) condensation of water vapor. air leaving the dehumidifier saturated at 285 k is mixed with a part of the original air, which has bypassed the dehumidifier. the resulting air stream is reheated to 320 k. it is desired that the final air contain water vapor not exceeding 0.03 kg/kg of dry air. calculate: (a) the dry air bypassed (in kg) per each kg of dry air sent through the dehumidifier (b) the water vapor condensed in the dehumidifier (in kg) per 100 m2 of air sent through it. (c) the volume of final air obtained per 100 m2 of air passed though the dehumidifier total pressure of system = 1 atm or 101.3 kpa vapor pressure of water at 285 k = 1.4 kpa vapor pressure of water at 320 k = 10.6 kpa data: