An insoluble wet granular material of 0.3m x 0.2m with 22mm thick is hold vertically. heat transfe from an air stream flowing perpendicular to the surface at a velocity of 5ft/s. the air stream has a wet bulb temperature of 29.6 c and dry bulb temperature of 50 c. the critical free moisture content os 0.03kg h2o/kg dry solid. the drying of this wet granular material is carried out in constant-free region.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

points

explanation:

it has both hydrogen and oxygen