Amixture of gases is analyzed and found to have the following volume composition: co2 12.0%, co 6.0, ch4 27.3, h2 9.9, and n2 44.8. how much will 38 [mol] of this mixture weigh, in [kg]?

Weight = 0.915 [kg]

Explanation:

When you have a mixture of gases

volumen composition = mol composition

With mol composition you calculate the molar mass of the mixture

CO2 : 44

CO: 28

CH4: 16

H2: 2

N2: 28

MM of Gas Mixture = 44*0.12+28*0.06+16*0.273+2*0.099+28*0.448 = 24.07

(Each molar mass * respective mol fraction)

Weight = 38 [mol] * 24.07 [g/mol] = 914.66 [g] = 0.915 [kg]

* Remember the unit of molar mass is: g/mol or kg/kmol or ton/mol-ton, etc

the answer is definitely c.