When 2.0 x 10-2 mole of nicotinic acid (amonoprotic
acid) is dissolved in 350 ml of water, the ph is 3.05.what is the
ka of nicotinic acid?

Ka of nicotinic acid =

Explanation:

pH = 3.05

No. of mol of nicotinic acid =

Volume of water = 350 mL = 0.0350 L

Molarity =

Molarity =

Nicotinic acid dissoctates as:

[H+] = 0.00089125 M

[A-] = 0.00089125 M

[HA} at equilibium = 0.05714 - 0.00089125 = 0.05624875 M

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.