Consider water at 1400 kpa and 200 c. what is the specific volume (in m3 /kg)?

Vw = 2.80907 E-3 m³/Kg

Explanation:

specific volume is the inverse of density:

⇒ Vw = 1 / ρ

∴ water at:

⇒ P = 1400 KPa * ( 1000 Pa / KPa ) = 1400000 Pa

⇒ T = 200°C = 473 K

Water at these conditions is found as saturated steam, specific volume would be:

⇒ Vw = R*T / P

∴ R = 8.3144 Pa.m³/ Kg.K

⇒ Vw = (( 8.3144 ) * ( 473)) / 1400000

⇒ Vw = 2.80907 E-3 m³/Kg

1 a

2 d

3 a

4 c

explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.