A
pure solvent freezes at 12.0 c. a solution of 0.980 g of the solute
and 13.870 g of solvent froze at 5.1 c. the molar mass of the
solute is 178.2 g/mol. calculate the freezing point depression
constant, kf for the solvent.

for solvent is

Explanation:

, where is depression in freezing point and m is molality of solution

Molality of solution (m) = (moles of solute/mass of solvent in kg)

                                      =

                                      = 0.396 mol/kg

So,

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.