Determine the theoretical yield of p2o5, when 3.07 g of p reacts with 6.09 g of oxygen in the following chemical equation
4 p + 5 o2 > 2 p2o5

14.2 grams

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

given mass of phosphorous (P) = 3.07 g

Molar mass of phosphorous (P) =  31 g/mol

Putting in the values we get:

given mass of oxygen = 6.09 g

Molar mass of oxygen =  32 g/mol

Putting in the values we get:

According to stoichiometry:

4 moles of phosphorous combine with 5 moles of oxygen

Thus 0.1 moles of phosphorous combine with = moles of oxygen

Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.

4 moles of phosphorous gives=  2 moles of

Thus 0.1 moles of phosphorous gives = moles of

mass of

Thus the theoretical yield of is 14.2 grams.

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.