Determine the percent yield of the following reaction when 2.80 g of p reacts with excess oxygen. the actual yield of this reaction is determined to by 3.89 g of p2o5.
4 p + 5 o2 > 2 p2o5

Answer : The percent yield of is, 30.39 %

Solution : Given,

Mass of P = 2.80 g

Molar mass of P = 31 g/mole

Molar mass of = 284 g/mole

First we have to calculate the moles of P.

Now we have to calculate the moles of

The balanced chemical reaction is,

From the reaction, we conclude that

As, 4 mole of react to give 2 mole of

So, 0.0903 moles of react to give moles of

Now we have to calculate the mass of

Theoretical yield of = 12.8 g

Experimental yield of = 3.89 g

Now we have to calculate the percent yield of

Therefore, the percent yield of is, 30.39 %