Hexane is a common laboratory solvent and a component of petrol. its combustion reaction is as follows: 2 c6h14 (9) + 19 02(9) +12 co2(g) + 14 h20(1) arh=-8326 kj mol-1 use the reaction enthalpy value to calculate the heat in (kj) released by combustion of 0.121 mol of hexane. (give your answer as a positive number to at least three significant figures and do not include the units in the answer box)

Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,

Explanation :

The given balanced reaction is,

Given:

Moles of hexane = 0.121 mol

= -8326 kJ/mol

The negative sign indicate that the reaction exothermic or amount of heat released.

As, 1 mole of hexane released heat = 8326 kJ

So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈

Therefore, the heat released by the combustion of 1.121 mol of hexane is .

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

the dissolution of polymer can be thermodynamically described in 2 steps.