1. make a 100 ml volume of 100 mm acetic acid (hac) hac (glacial, 100%, 17.4 m, 1.05 g/ml, mw 60.05) ddh,0 ml add to 100 ml measure 250 ml beaker. add ml of ddh20 using a 100-ml graduated cylinder and transfer this volume to a ul of 100 mm hac to the water. mix with a stir bar.

To make 100 mL of a solution 100mM of acetic acid you need to add 0,57 mL of glacial acetic acid and mix with 99,43 mL of H₂O

Explanation:

Molarity is a way to express concentration in a solution, in units of moles of solute per liter of solution.

To know how to do 100 mL of a solution 100mM of acetic acid it is necessary to know, first, the moles of this substance with the desired volume and concentration , thus:

0,100 L × = 0,0100 moles of acetic acid

These moles are obtained from glacial acetic acid. Thus, it is necessary to convert these moles to grams with molar weight and then to mililiters with density:

0,0100 moles × × = 0,57 mL of glacial acetic acid

Thus, to make 100 mL of a solution 100mM of acetic acid you need to add 0,57 mL of glacial acetic acid and mix with 99,43 mL of H₂O -The necessary to obtain 100 mL-

I hope it helps!