15 g of anhydrous calcium chloride is dissolved in 185 ml of water. what is molarity of the prepared solution? 81.1 m o0.73 m 0.081 m o0.073 m 1.07 m

When you prepared the solution, you will find that the molarity is 0.73M

Explanation:

First of all you should get by the periodic table, molar mass in the anhydrouds calcium.

CaCl2 · 0H20 = 110.98 g/m

Now we have to find out how many mols are 15 g.

So 15g / 110.98 g/m = 0.135 moles

This moles are in 185 ml of water. Molarity as you should know are moles of solute in 1 L of solution (either 1000 ml)

185 ml 0.135 moles

1000 ml x    x = (1000*0.135) /185 = 0.730M

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