Chemistry, 17.09.2019 23:00 impura12713
Successive deprotonations the ( − ) charge density on the resulting anion. the (−) charge density on the resulting anion. this results in unfavorable electrostatic between the carboxylate anions, which reduces the likelihood that a proton would it is more favorable for the proton to remain bound to reduce unfavorable charge
Answers: 3
Chemistry, 22.06.2019 04:00
Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.
Answers: 2
Chemistry, 22.06.2019 05:50
Fill in the coefficients that will balance the following reaction: a0cr2(so4)3 + a1agno3 -> a2cr(no3)3 + a3ag2so4
Answers: 1
Chemistry, 22.06.2019 10:00
The reactions shown here can be combined to make the overall reaction c(s) + h2o(g) ⇌ co(g) + h2(g) by reversing some and/or dividing all the coefficients by a number. a. c(s) + o2(g) → co2(g) k=1.363×10^69 b. 2 h2(g) + o2(g) → 2 h2o(g) k=1.389×10^80 c. 2co(g) + o2 (g) → 2 co2(g) k=1.477×10^90
Answers: 1
Successive deprotonations the ( − ) charge density on the resulting anion. the (−) charge density o...
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