Chemistry, 18.09.2019 05:30 alondrachon
A100.0 gram sample of aluminum (specific heat = 0.900 j * g^-1 * degrees celsius^-1) in boiling water is added to an insulated cup containing 50.0 grams of water at 5.00 degrees celsius. what will the final temperature of the mixture be? the specific heat of the water is 4.184 j * g^-1 * degrees celsius^-1.
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A100.0 gram sample of aluminum (specific heat = 0.900 j * g^-1 * degrees celsius^-1) in boiling wate...
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