An alloy of al and cu was treated with aq hcl .the aluminium dissloved according to the reaction al+3h =al+3/2h2,but the cu remained as the pure metal .a 0.350 gm sample of the alloy gave 415cc of h2 measured at 273.1 °k and 1 atm pressure .what is the wt percentage of the al in the alloy

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts

i have no clue hope you find the answer

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2