Propane, c3hs. is flammable and used in rural areas where natural gas is not available. what is the coefficient of oxygen in the balanced equation for the combustion of propane? _c3 hp)* 026) > _co24) _h206) a) 1 b) 5 c) 10 d) 7 e) none of the above

The coefficient of oxygen in this balanced reaction is 5 ( option B)

Explanation:

Propane = C3H8

The process of combustion = adding oxygen (O2)

In this process propane will be consumed and CO2 and H2O will be produced.

C3H8 + O2 → CO2 + H2O

First we'll balance on both sides all H-atoms: left we have 8x H and on the right side we have 2x H so we have to multiply the right side ( H2O) by 4.

This gives us:

C3H8 + O2 → CO2 + 4H2O

Now we have on both side 8x H

On the left side we have 3x C, and 1x C on the right side. So we have to multiply CO2 on the right side by 3

This gives us: C3H8 + O2 → 3 CO2 + 4 H2O

On the left side we have 2x O but on the right side we have 10x O

We have to multiply O2 on the left side by 5, to equal this.

So finally, we'll have: C3H8 + 5 O2  → 3 CO2 + 4 H2O

We can see that the coefficient of oxygen in this balanced reaction is 5 ( option B)

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: