How many grams of nai are needed to prepare 400.0 ml of 0.0500 m nai solution?

We need 3.00 grams NaI

Explanation:

Step 1: Data given

Volume = 400.0 mL = 0.400L

Molarity = 0.0500 M

Molar mass of NaI = 149.89 g/mol

Step 2: Calculate moles

Moles NaI = molarity * volume

Moles NaI = 0.0500 M * 0.400 L

Moles NaI = 0.02 moles

Step 3: Calculate mass NaI

Mass NaI = moles NaI * molar mass NaI

Mass NaI = 0.02 moles * 149.89 g/mol

Mass NaI = 3.00 grams

We need 3.00 grams NaI

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.