The n2o4−no2 reversible reaction is found to have the following equilibrium partial pressures at 100∘c. calculate kp for the reaction. n2o4(g)⇌2no2(g) 0.0005 atm 0.095 atm express your answer using two significant figures.

for the reaction is 18.05

Explanation:

Equilibrium constant in terms of partial pressure () for this reaction can be written as-

where and are equilibrium partial pressure of and respectively

Hence = 18.05

So, for the reaction is 18.05

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atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8