If 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?

The amount of sodium chloride formed is 58.44 grams.

Given:

22.99 g of sodium completely reacts with 35.45 g of chlorine.

To find:

The mass of sodium chloride formed

Solution:

Mass of sodium = 22.99 g

Mass of chlorine = 35.45 g

The equation of chemical reaction between sodium and chlorine:

According to the question, 22.99 grams of sodium completely reacts with 35.45 grams of chlorine which means no reactants were left unreacted.

The mass of reactants =

The mass of product = Mass of NaCl formed =?

According to the law of conservation of mass:

Mass of reactants = Mass of products

Mass of reactants = 58.44 g

Mass of products = Mass of reactants = 58.44 g

Mass of sodium chloride formed = 58.44 g

The amount of sodium chloride formed is 58.44 grams.

Learn more about the law of conservation of the mass:

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The answer to your question is: HCl = 58.44 g

Explanation:

To solve this problem, we must remember the law of conservation of mass that says that, matter cannot be created or destroyed, only changes its form.

That means that, the mass of the reactants must be equal to the mass of the products.

               Process

                    Sodium (Na)  +    Chlorine (Cl)   ⇒     Sodium chloride (HCl)

                         22.99 g              35.45 g                            x

              22.99 + 35.45 = HCl

              HCl = 58.44 g

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