If the oxidation state of h is +1 and o is −2, what is the oxidation state of c in c2h4o? −1 +2 +1 −2

-1

Explanation:

The sum of the oxidation states of all the atoms in a neutral compound is zero. Then the following equation must be satisfied:

number of atoms of C * oxidation state of C + number of atoms of H * oxidation state of H + number of atoms of O * oxidation state of O = 0

Replacing with data and calling the unknown x, we get:

2*x + 4*1 + 1*(-2) = 0

2*x + 2 = 0

x = (-2)/2

x = -1

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.