Which statement about 2‑methyl‑1‑propanol, (ch3)2chch2oh , and 1,3‑propanediol, hoch2ch2ch2oh is true? 2‑methyl‑1‑propanol is more soluble in water than 1,3‑propanediol because 2‑methyl‑1‑propanol has a smaller molecular mass. 2‑methyl‑1‑propanol is more soluble in water than 1,3‑propanediol because 2‑methyl‑1‑propanol forms fewer hydrogen bonds with water. 1,3‑propanediol is more soluble in water than 2‑methyl‑1‑propanol because 1,3‑propanediol has a smaller molecular mass. 1,3‑propanediol is more soluble in water than 2‑methyl‑1‑propanol because 1,3‑propanediol can form multiple hydrogen bonds with water.

Propane-1,3-diol is more soluble in water than 2-methylpropan-1-ol because propane-1,3-diol can form more hydrogen bonds with water.

Explanation:

The structures of the two compounds are shown below.

The two compounds have almost the same molecular mass (72 vs 74), so the important factor must be the number of OH groups.

Thus, propane-1,3-diol is more soluble in water than 2 methyl 1 propanol because propane-1,3-diol can form more hydrogen bonds with water.

A and C are wrong. The molecular masses of the two compounds are almost identical.

B is wrong. Fewer hydrogen bonds would make 2-methylpropan-1-ol less soluble.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6