Amixture of 50 wt% methane, 35 wt% ethane, and 15 wt% propane. determeine the mole fraction of methane.
(can use a basis of 100kg)
b) what is the average molecular weight of the mixture?
for (b) can use m = \sum yi mi where m = average molecular weight, yi= mole fraction of individual substance, mi = molecular weight of individual substance or can also use 1/m = \sum xi / mi where 1/m = average molecular weight, xi = mass fraction of individual substance, mi = molecualr weight of individual substance.

a) Molar fraction:

Methane: 67,5%

Ethane: 25,1%

Propane: 7,4%

b) Molecular weight of the mixture: 25,16 g/mol

Explanation:

with a basis of 100 kg:

Moles of methane:

500 g × = 31,2 moles

Mass of ethane

350 g × = 11,6 moles

Mass of propane

150 g × = 3,4 moles

Total moles: 31,2 moles + 11,6 moles + 3,4 moles = 46,2 moles

Molar fraction of n-methane:

=67,5%

Molar fraction of ethane:

= 25,1%

Molar fraction of propane:

= 7,4%

b) Average molecular weight:

= 25,16g/mol

I hope it helps!

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

answer; talc and gypsum;