The ideal gas law is pv-nrt for r in units of 0.08206 lit atm k-1.mol-1 determine the density of argon gas at 10.0 atm and 25.0°c in units of grams per cm3.

The density of argon gas is

Explanation:

To calculate the density of gas, we use the equation given by ideal gas equation:

Number of moles (n) can be written as:

where, m = given mass

M = molar mass

where,

which is known as density of the gas

The relation becomes:

   .....(1)

We are given:

M = molar mass of argon = 39.95 g/mol

R = Gas constant =

T = temperature of the gas =

P = pressure of the gas = 10.0 atm

Putting values in equation 1, we get:

Converting the calculated density into , we use the conversion factor:

Converting the density into , we get:

Hence, the density of argon gas is

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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