The reynolds number, re, is a dimensionless number used to characterize different flow regimes in a fluid. the reynolds number can be defined as dvd re= where d is the diameter of the pipe, v is the mean fluid velocity, p is the density of the fluid, and p is the dynamic viscosity of the fluid. what is the reynolds number of blood leaving the heart through the aorta if it has a dynamic viscosity of y= 3.70 cp (centipoise), a density of p = 1051 kg/m, travels at a mean fluid velocity of v = 34.3 cm/s, and the diameter of the aorta is d = 2.15 cm?

Re=2094,76

Explanation:

For a fluid that circulates inside a straight circular pipe, the Reynolds number is given by:

where (using the international measurement system):

To solve the probelm, we just need to replace our data using THE CORRECT UNITS in the Reynolds number equation. So we have:

ρ=1051 kg/m3,

v=34,3 cm/s=0,343 m/s

D=2,15 cm = 0,0215 m

μ = 3,7 cp * 10^-3 Pa.s/1 cp = 3,7*10^-3 Pa.s

Replacing in the main equation:

So the Reynolds number is 2094,76 (note that the Reynolds number is a dimensionless quantity).

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

i believe the answer is a.