Avat of water to be used in a chemical reaction starts at a height of 1.8 meters. the tank itself has a diameter of 0.8 meters, but unfortunately, there is a small leak at the bottom of the tank with a rate of leakage proportional to the hydrostatic pressure at the bottom of the tank. knowing this info, how long before half the tank has leaked out? other info: (hydrostatic pressure= r*g*h; where r= density of fluid, g=acceleration due to gravity, h=height of fluid above object); density of fluid = 1000kg/m^3 * i think this is supposed to be a diff. eq problem; i have the setup but i can't figure out what diff. eq i need to actually perform this calculation. i think its some form of dv/dt since q= flow rate =dv/dt, but i'm not sure *
** edit: i edited the first sentence to reflect that 1.8 meters in the tank is the height (at least i assume) and the proportion i believe is that the flow rate is equal to the hydrostatic pressure at the bottom of the tank, so i think p(hydrostatic)=leakage rate= (1000)*(9.8)*(1.8)= 17,640 is the way to go.